A child has three different kinds of chocolates costing Rs. 2, Rs. 5 and Rs. 10.

Ques - A child has three different kinds of chocolates costing Rs. 2, Rs. 5 and Rs. 10. He spends total Rs. 120 on the chocolates. What is the minimum possible number of chocolates, he can buy, if there must be atleast one chocolate of each kind?

(a) 22

(b) 19

(c) 17

(d) 15

Solution - 

Given,

A child has three different kinds of chocolates costing = Rs. 2, Rs. 5 and Rs. 10.

He spends total on the chocolates =Rs. 120

There must be atleast one chocolate of each kind.

Here,

The no. of chocolates inversely proportional to the rupees per chocolate.

So,

For minimum no. of chocolates, He must be buy more of costliest Chocolates.

Therefore,

No. of Rs. 10 Chocolates = 10 × 10

No. of Rs. 10 Chocolates = 100

He spends total on the chocolates =Rs. 120

Therefore,

Left money = 120 - 100

= 20

Now for left Rs. 20

He can buy no. of Rs. 5 chocolates = 5 × 2

 = 10 

Now,

He can Buy no. of Rs. 2 chocolates = 2 × 5

= 10

Thus,

Minimum No. of chocolates = 10 + 5 + 2

Minimum No. of chocolates = 17.

Hence,

The correct answer is option (c) 17.

Thank You