GATE - 2004 | OS | Consider a fully associative cache with 8 cache blocks (numbered 0-7)

GATE - 2004 [Operating System]

Question:

Consider a fully associative cache with 8 cache blocks (numbered 0-7) and the following sequence of memory block requests: 4, 3, 25, 8, 19, 6, 25, 8, 16, 35, 45, 22, 8, 3, 16, 25, 7 If LRU replacement policy is used, which cache block will have memory block 7?

A	4
B	5
C	6
D	7

  

Solution:

Option (B) is Correct.

When 45 comes, the cache contents are:
4, 3, 25, 8, 19, 6, 16, 35

CPU array (first element being least recently used)
[4, 3, 19, 6, 25, 8, 16, 35]

So, 45 replaces 4.

45, 3, 25, 8, 19, 6, 16, 35 [3, 19, 6, 25, 8, 16, 35, 45]
Similarly, 22 replaces 3 to give,

45, 22, 25, 8, 19, 6, 16, 35 [19, 6, 25, 8, 16, 35, 45, 22]
8 hits in cache.

45, 22, 25, 8, 19, 6, 16, 35 [19, 6, 25, 16, 35, 45, 22, 8]
3 replaces 19,

45, 22, 25, 8, 3, 6, 16, 35 [6, 25, 16, 35, 45, 22, 8, 3]
16 and 25 hits in cache,

45, 22, 25, 8, 3, 6, 16, 35 [6, 35, 45, 22, 8, 3, 16, 25]
Finally, 7 replaces 6, which is in block 5.

Thank You