Solution -
Let,
The initial cost of a bike = 100x
then initial cost of a car = 100x + 400% of 100x
= 100x + (400/100) × 100x
= 100x + 400x
= 500x
Increase in the cost of the car = 15%
= 500x + (15/100) × 500x
= 500x + 75x
= 575x
Increase in the cost of the car = 20%
= 100x + (20/100) × 100x
= 100x + 20x
= 120x
Initial cost of 10 bikes = 100x × 10
= 1000x
Initial cost of 5 cars = 500x × 5
= 2500x
New cost of 10 bikes = 120x × 10
= 1200x
New cost of 5 cars = 575x × 5
= 2875x
Change in cost of bikes = new cost - initial cost
= 1200x - 1000x
= 200x
Change in cost of cars = new cost - initial cost
= 2875x - 2500x
= 375x
Thus,
The total increase in the cost of the 5 cars and 10 bikes is = 200x + 375x
= 575x
Total initial cost = 1000x + 2500x
= 3500x
Percentage increase in the cost = (575x/3500x) × 100
= 575/35
= 16(3/7)
Hence,
The correct option is (b) 16(3/7)%.
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