Solution -
The number of days required by a kirlosker pump to fill the tank = 6 × 7
= 42 days
The number of days required by a USHA pump to fill the tank = 2 × 18
= 36 days
Thus,
The efficiency is inversely proportional to the number of days.
Therefore,
Efficiency of a kirlosker pump = 36
Efficiency of a USHA pump = 42
So,
Ratio of efficiency of kirlosker pump and USHA pump = 36/42
= 6/7
= 6 : 7
The ratio of the efficiency of a kirlosker pump and a USHA pump is 6 : 7.
Hence,
The correct answer is option is (a) 6 : 7.
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