**A is two years older than B who is twice as old as C. If the total of the ages of A, B and C be 27, then how old is B?**

Let's solve the problem step by step and explain the process in detail.

Given information:

- A is two years older than B.
- B is twice as old as C.
- The total of the ages of A, B, and C is 27.

Let's assume C's age as x years. Using this assumption, we can calculate the ages of A and B.

- B is twice as old as C, so B's age is 2x.
- A is two years older than B, so A's age is 2x + 2.

To find the values of x, A, and B, we will set up an equation based on the total of their ages.

The equation can be written as: A + B + C = 27

Substituting the values of A, B, and C: (2x + 2) + (2x) + x = 27

Simplifying the equation: 5x + 2 = 27 5x = 27 - 2 5x = 25 x = 25/5 x = 5

We have found the value of x, which represents C's age. C's age is 5 years.

Now, we can calculate the ages of A and B using the values we have obtained.

A = 2x + 2 A = 2 * 5 + 2 A = 10 + 2 A = 12

B = 2x B = 2 * 5 B = 10

Hence, we have determined that B is 10 years old.

In conclusion, based on the given information and solving the equations, we find that B is 10 years old.

Thank You