Solution -
We have,
Total of 33 children aged below 18 were involved.
The ratio of male to female in A, B and C was 4 : 3, 3 : 2 and 5 : 4 respectively.
The number of male and female in factories A, B & C are:
Male Female
A: 4x 3x
B: 3y 2y
C: 5z 4z
If the no. of female children working in the factories B and C be equal.
So,
No. of female children in B = No. of female children in C
⇒ 2y = 4z
⇒ y = 2z
Now,
Total no. of children in factories A, B & C = 33
⇒ (4x + 3x) + (3y + 2y) + (5z + 4z) = 33
⇒ (7x) + (5y) + (9z) = 33
⇒ (7x) + [5(2z)] + (9z) = 33 (given - y = 2z )
⇒ 7x + 10z + 9z = 33
⇒ 7x + 19z = 33
Thus,
The only value possible for z is 1
⇒ 7x + (19×1) = 33
⇒ 7x + 19 = 33
⇒ 7x = 33 - 19
⇒ 7x = 14
⇒ x = 2
Therefore,
No. of female children working in factory A = 3x
= 3 × 2
= 6
Thus,
The no. of female children working in factory A is 6.
Hence,
The correct answer is option (d) 6.
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