Consider the following schedule S of transactions T1 and T2:
A |
S is serializable only as T1, T2 |
B |
S is serializable only as T2, T1 |
C |
S is serializable both as T1, T2 and T2, T1 |
D |
S is serializable either as T1 or as T2 |
E |
None of these |
The given statement is not serializable as cycle exist in precedence graph. Therefore, options A, B, C, D are not correct.
Thank You