GATE - 2008 | OS | If the time-slice used in the round-robin scheduling policy is more than

GATE - 2008 | OS | If the time-slice used in the round-robin scheduling policy is more than
Posted on 15-02-2022

GATE - 2008 [Operating System]

Question:

If the time-slice used in the round-robin scheduling policy is more than the maximum time required to execute any process, then the policy will

A

degenerate to shortest job first

B

degenerate to priority scheduling

C

degenerate to first come first serve

D

none of the above

    

Solution:

Option (C) is Correct.

Round robin executes processes in FCFS manner with a time slice. In this time slice becomes long enough, so that a process finishes within it, it becomes FCFS.

 

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