GATE - 2016 | OS | Consider a computer system with 40-bit virtual addressing and page size
Posted on 09-02-2022
GATE - 2016 [Operating System]
Question:
Consider a computer system with 40-bit virtual addressing and a page size of sixteen kilobytes. If the computer system has a one-level page table per process and each page table entry requires 48 bits, then the size of the per-process page table is __________ megabytes.
|
A |
384 MB |
|
B |
385 MB |
|
C |
386 MB |
|
D |
387 MB |
Solution:
Option (A) is Correct
From the above question, we got the following information.
Size of memory = 240
Page size = 16 KB = 214
No. of pages = size of Memory / page size
= 240/ 214 = 226
Size of page table = 226 * 48 / 8 bytes
= 26 * 6 MB = 384 MB
Thank You