Solution -
Let,
The Maximum marks = 100x
A candidate got 30% marks = 30/100 × 100x
= 30x
Failed by 30 marks,
Therefore,
The passing marks will be = 30x + 30
Again,
The passing marks are 60% of the total marks
Therefore,
The passing marks = 60x
A/C
60x = 30x + 30
60x - 30x = 30
30x = 30
x = 1
Therefore,
The Maximum marks = 100x
The maximum marks = 100
Hence,
The correct option is (d) 100.
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