Solution - In Ruchika's wallet there are Rs. 16.
Firstly,
Change the rupees into paise = 16 × 100
= 1600
consisting of 10 paise, 20 paise and Re. 1 coins.
Let,
10 paise = 10x
20 paise = 20y
Re. 1 = 100z
A/C
10x + 20y + 100z = 1600
The ratio of number of coins 10 paise coins and 20 paise is 6 : 1 (given)
x : y = 6 : 1
x/y = 6/1
x = 6y
10x + 20y + 100z = 1600
10(6y) + 20y + 100z = 1600
60y + 20y + 100z = 1600
80y + 100z = 1600
20 (4y + 5z) = 1600
4y + 5z = 1600/20
4y + 5z = 80
Now,
Take z = 1,2,3,4,5 and check
we get,
z = 4
4y + 5z = 80
4y + 5(4) = 80
4y = 80 - 20
4y = 60
y = 60/4
y = 15
So,
Re. 1 = 100z
= 100(4)
= 400paise
Therefore,
Minimum 4 coins of Re. 1 will be there.
Hence,
The correct answer is option (d) 4.
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