Solution -
Let,
The weight of kerosene = x
Then,
The weight of Petrol = 7x
And,
THe weight of Castrol Mobil = 18x
Now,
Let,
The ratio of Petrol & Mobil = P : M
Then,
Total Mixture = P + M
Total Weight = (P + M) 11x ( as it is 11 times as heavy as kersoene)
But,
Total weight = 7Px + 18Mx
(P + M) 11x = 7Px + 18Mx
11Px + 11Mx = 7Px + 18Mx
11Px - 7Px = 18Mx - 11Mx
4Px = 7Mx
4P = 7M
P/M = 7/4
Ratio of P : M = 7 : 4
Thus,
The ratio of petrol and Mobil in the new mixture to get the mixture which must be 11 times as heavy as kerosene should be 7 : 4.
Hence,
The correct answer is option (b) 7 : 4.
Thank You